判断数组中奇数偶数的个数并求和

判断数组中奇数偶数的个数并求和

package pratice;
public class Sum {
    public static void main(String[] args) {
        int arr[]=new int[]{1,2,3,92,45,67,68,57};
        int sum=0;
        int sums=0;
        int m=0;
        int n=0;
        for(int i=0;i<arr.length;i++) {
            if (arr[i] % 2 == 0) {
                sum += arr[i];
                n++;
            } else{
                sums+=arr[i];
                m++;
            }
        }
        System.out.println("奇数个为数"+m+",奇数和"+sums);
        System.out.println("偶数个为数"+n+",偶数和"+sum);
    }
}